Pre-equilibrium approach q


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Katherine Grillo 1B
Posts: 69
Joined: Fri Sep 28, 2018 12:28 am

Pre-equilibrium approach q

Postby Katherine Grillo 1B » Sat Mar 16, 2019 7:32 pm

Given general reaction mechanism like

Step 1 (Fast): 2A + B -> C
Step 2 (Slow): C + D -> 2E

Would the expression for the rate of formation of the product E using the pre-equilibrium approach be equal to (2k1k2/k1')[A]^2[B][D] ?

This is question 12 from Lyndon's practice final btw

Alana Sur 3B
Posts: 61
Joined: Fri Sep 28, 2018 12:25 am

Re: Pre-equilibrium approach q

Postby Alana Sur 3B » Sat Mar 16, 2019 8:23 pm

Yes, that's correct

Nicole Elhosni 2I
Posts: 62
Joined: Fri Sep 28, 2018 12:28 am

Re: Pre-equilibrium approach q

Postby Nicole Elhosni 2I » Sat Mar 16, 2019 8:24 pm

Yes that is the answer.

isarose0
Posts: 62
Joined: Fri Sep 28, 2018 12:15 am

Re: Pre-equilibrium approach q

Postby isarose0 » Sat Mar 16, 2019 9:15 pm

Why is the k1 multiplied by 2?


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