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when writing the rate laws for elementary reactions the textbook says "The reverse of step 2 is too slow to affect the rate and so is not included." (634) how are we supposed to know when a reaction is to slow to include?
We only use the reverse reaction if the step is at equilibrium, because the step is too slow there is no bottleneck or build and therefore the step is not equilibrium and the reverse reaction is not taken into account. The problem should indicate if the step is slow or fast, where fast steps are usually considered to be at equilibrium and therefore have a forward and reverse reaction rate
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