## Collisions in Unimolecular Reactions

$K = \frac{k_{forward}}{k_{reverse}}$

Jessica Li 4F
Posts: 115
Joined: Fri Aug 09, 2019 12:16 am

### Collisions in Unimolecular Reactions

In class today, Lavelle brought up how in reactions, the reactants need to collide with enough energy (activation energy) for the reaction to proceed. How does this apply to unimolecular reactions, where there is only one reactant and it doesn't need to collide?

CynthiaLy4F
Posts: 103
Joined: Sat Jul 20, 2019 12:16 am

### Re: Collisions in Unimolecular Reactions

The reactant would still collide with solvent molecules, but that is not shown in the rate law.

Andrew Liang 1I
Posts: 105
Joined: Fri Aug 30, 2019 12:18 am

### Re: Collisions in Unimolecular Reactions

Dr. Lavelle said that in unimolecular reactions the molecule does not have to collide with other molecule. The molecule can collide with the side of the beaker or with solvent that is not a part of the chemical reaction. These collision can cause bond breaking in that one molecule resulting in unimolecular reaction