## 7.23 part b

$K = \frac{k_{forward}}{k_{reverse}}$

AKhanna_3H
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Joined: Wed Sep 18, 2019 12:19 am

### 7.23 part b

Could someone explain part b of this question? I understand that the slow step of the reaction determines the rate but how do you replace the intermediate in the rate law using the other steps in the mechanism?

Posts: 50
Joined: Mon Jun 17, 2019 7:24 am

### Re: 7.23 part b

I believe what you are asking is how to remove the intermediate from the analysis - the way to do this is by assuming that first step is at equilibrium, so the rate of production of the intermediate in the first step can be ignored. Thus, the slow step determines the rate law.

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