## Endgame 15b

$K = \frac{k_{forward}}{k_{reverse}}$

chari_maya 3B
Posts: 108
Joined: Sat Sep 07, 2019 12:18 am

### Endgame 15b

Can someone explain question 15b on Endgame?

The lab finds that with these conditions, yield a pseudo rate constant k'. Show how k' is related to the real overall rate constant k.

I am a little confused what the significance of a pseudo rate constant is. I also just don't understand the solution given.

TanveerDhaliwal3G
Posts: 105
Joined: Fri Aug 30, 2019 12:17 am

### Re: Endgame 15b

I think the k' is supposed to signify the combination of the first rate constant and the concentration of A

Emily Burghart 1k
Posts: 50
Joined: Wed Sep 18, 2019 12:17 am

### Re: Endgame 15b

TanveerDhaliwal3G wrote:I think the k' is supposed to signify the combination of the first rate constant and the concentration of A

How did you get that from the problem? Is there a simple way of figuring that out?

CNourian2H
Posts: 106
Joined: Fri Aug 30, 2019 12:16 am

### Re: Endgame 15b

Ya I dont understand how to get it directly.

CNourian2H
Posts: 106
Joined: Fri Aug 30, 2019 12:16 am

### Re: Endgame 15b

Oh i guess pseudo rate constant k' is just using the reactant concentration that the rate is dependent on. that would be [B].

Jessica Chen 2C
Posts: 103
Joined: Thu Jul 11, 2019 12:17 am

### Re: Endgame 15b

Yeah I guess the pseudo rate constant allows us to focus on seeing how one specific reactant’s concentration affects rate. By making the concentration of A super high, it’s essentially not changing as the reaction proceeds, and thus we can include it in k’.