Homework #17
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 81
- Joined: Fri Sep 29, 2023 11:27 am
Homework #17
I'm not sure how to manipulate the delta H and activation energy of the forward reaction to find the activation energy of the reverse reaction. Could someone please explain.
-
- Posts: 71
- Joined: Fri Sep 29, 2023 12:05 pm
Re: Homework #17
If the delta H is given as well as the activation energy, the reverse reaction will have an activation energy that is the activation energy of the forward reaction minus the deltaH.
-
- Posts: 41
- Joined: Wed Jan 11, 2023 8:20 am
Re: Homework #17
Both formulas involve the E(reactants) so manipulate the formulas to get E(reactants) for both. Then set the remaining expressions equal to each other. From there you should be able to find E(products)-E(transition) to get Ea of the reverse reaction.
-
- Posts: 42
- Joined: Tue Nov 14, 2023 9:06 am
-
- Posts: 77
- Joined: Fri Sep 29, 2023 12:20 pm
Re: Homework #17
In a chemical reaction, the forward reaction involves breaking bonds in the reactants and forming new bonds to create products. The activation energy (Ea) represents the energy barrier that must be overcome for the reaction to occur.
To manipulate the delta H (enthalpy change) and activation energy of the forward reaction to find the activation energy of the reverse reaction, you can use the relationship between the forward and reverse reactions.
Ea(forward) - Ea(reverse) = ∆H
You can manipulate this equation.
To manipulate the delta H (enthalpy change) and activation energy of the forward reaction to find the activation energy of the reverse reaction, you can use the relationship between the forward and reverse reactions.
Ea(forward) - Ea(reverse) = ∆H
You can manipulate this equation.
Re: Homework #17
for this problem all you have to do is subtract to find your answer. Ea(forward- Ea(reverse) Delta H
Return to “Arrhenius Equation, Activation Energies, Catalysts”
Who is online
Users browsing this forum: No registered users and 4 guests