## Question 15.79

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

Sydney Wu 2M
Posts: 50
Joined: Fri Jul 22, 2016 3:00 am

### Question 15.79

"In the reaction of Her with the reactive intermediate CH3CH=CHCH2+, at low temperatures the predominant product is CH3CHBrCH=CH2, but at high temperatures, the predominant product is CH3CH=CHCH2Br. (a) Which product is formed by the pathway with the larger activation energy? (b) Does kinetic control predominate at low or high temperatures? Explain your answers."

I am unsure on where/how to begin. Can someone please explain?

Thank you!

Gabrielle_Giang_2J
Posts: 11
Joined: Wed Sep 21, 2016 2:59 pm

### Re: Question 15.79

For a, CH3CH = CHCH2Br is formed by the pathway with higher activation energy because the positive charge on the reactive intermediate is on a carbon atom.
For b, kinetic control predominates at low temperatures. The lower activation energy barrier causes a faster reaction from a larger rate constant.