## Catalyst that is used and produced

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

garrett_perozich
Posts: 15
Joined: Wed Sep 21, 2016 2:57 pm

### Catalyst that is used and produced

On quiz two, we had a reaction with two steps:

Step 1: this was the slow step and used a catalyst
Step 2: this was a fast step and produced the same catalyst

So my question is, why would the catalyst be a part of the rate law equation if it is produced as soon as it is used up?

Martin_Sarafyan_2K
Posts: 11
Joined: Wed Sep 21, 2016 2:56 pm

### Re: Catalyst that is used and produced

The rate determining step is the slow step, if the catalyst is within the slow step, then it affects the rate itself because it lowers Ae. Even, if it isnt in the overall reaction, it affects the rate because of its presence.

Samuel_Vydro_1I
Posts: 21
Joined: Fri Jul 22, 2016 3:00 am

### Re: Catalyst that is used and produced

Well the more catalyst, the more reactant it can catalyze. A lot of enzyme use surface area, moree enzyme means more surface area

veeksha25
Posts: 29
Joined: Wed Sep 21, 2016 2:56 pm

### Re: Catalyst that is used and produced

Do you include the catalyst when writing the rate law?

Joseph_Ghaly_2L
Posts: 22
Joined: Fri Jul 22, 2016 3:00 am

### Re: Catalyst that is used and produced

veeksha25 wrote:Do you include the catalyst when writing the rate law?

Yes, because it affects the rate of the reaction.