## Problem 15.61

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

Amy Zheng 2l
Posts: 57
Joined: Fri Sep 29, 2017 7:04 am

### Problem 15.61

Where did the solution manual get the equation ln(k'/k)=Ea/r(1/T-1/T') from?

Sabah Islam 1G
Posts: 50
Joined: Sat Jul 22, 2017 3:01 am

### Re: Problem 15.61

I believe this equation was derived from the equation on the constants and equations sheet: k=A exp(-Ea/RT), where ln(k'/k) was used because of the reaction being first order and T being extracted from (-Ea/RT) to become Ea/r(1/T - 1/T'). I'm not entirely sure about this, but I hope this helps.

Christy Lee 2H
Posts: 73
Joined: Fri Sep 29, 2017 7:07 am
Been upvoted: 1 time

### Re: Problem 15.61

Do you know where A went though?

Katie Blann 1E
Posts: 29
Joined: Tue Nov 15, 2016 3:00 am

### Re: Problem 15.61

I am also confused about where this equation came from can anyone elaborate on this more?

Paula Dowdell 1F
Posts: 72
Joined: Tue Nov 15, 2016 3:00 am

### Re: Problem 15.61

Does anyone know why they used kilojoules in this problem? When i use regular joules (R= 8.314 J/Kxmol) I get a completely different answer.

Seth_Evasco1L
Posts: 54
Joined: Thu Jul 27, 2017 3:00 am

### Re: Problem 15.61

I calculated using joules and had my answer off by a factor of 103 which is reasonable because converting to kilojoules would provide me with the same answer as the solution manual. Perhaps there was some miscalculation in the process?