## Activation Energy Temperature Dependence

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

Sirajbir Sodhi 2K
Posts: 47
Joined: Sat Jul 22, 2017 3:00 am

### Activation Energy Temperature Dependence

Why is activation energy independent of temperature? I would think that it would decrease as temperature increases because of the increased rate of collisions?

lindsay lathrop 2C
Posts: 29
Joined: Sat Jul 22, 2017 3:00 am

### Re: Activation Energy Temperature Dependence

Activation energy is technically the minimum amount of Kinetic Energy needed for a a collision to result in a reaction (according to the collision theory). The higher the temperature the more Kinetic energy is present meaning the higher the likelihood we will reach this level and end up with a reaction as a result of the collision. With a rise of temperature we are climbing the reaction graph approaching the activation barrier, therefore, we are closer to the activation energy but the activation energy has not itself changed.

lindsay lathrop 2C
Posts: 29
Joined: Sat Jul 22, 2017 3:00 am

### Re: Activation Energy Temperature Dependence

Adding on: Although it is mostly independent, what you did point does happen to a certain extent which is why the book states "Both A and Ea are nearly independent"

Christy Lee 2H
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### Re: Activation Energy Temperature Dependence

Does what you described have to do with the frequency factor at all?

Akash_Kapoor_1L
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### Re: Activation Energy Temperature Dependence

I'm pretty certain that the variable A is also defined as the frequency factor.

Sirajbir Sodhi 2K
Posts: 47
Joined: Sat Jul 22, 2017 3:00 am

### Re: Activation Energy Temperature Dependence

I think it does have to do with the frequency factor more than the activativation energy -- thank you.