Page 1 of 1

### 15.61

Posted: Mon Mar 12, 2018 2:49 pm
This question gives us two different values for the rate constant of a first-order reaction. One is 0.76 s-1 at 1000 K and the other is 0.87 s-1 at 1030 K. How do we know which value is k and which value is k'? They don't explicitly specify it in the question.

### Re: 15.61

Posted: Mon Mar 12, 2018 2:53 pm
k would be the rate constant of the forward reaction. k' would be the rate constant of the reverse reaction.

### Re: 15.61

Posted: Mon Mar 12, 2018 2:56 pm
Swetha Sundaram 1E wrote:k would be the rate constant of the forward reaction. k' would be the rate constant of the reverse reaction.

But they don't specify which is the rate constant for the forward reaction and which is the rate constant for the reverse reaction

### Re: 15.61

Posted: Mon Mar 12, 2018 3:19 pm
For that question I was also wondering if we would be given the formula on the final formula sheet? I don't think I saw it on the formula sheet posted on the 14B website

### Re: 15.61

Posted: Tue Mar 13, 2018 9:48 am
Beza Ayalew 1I wrote:For that question I was also wondering if we would be given the formula on the final formula sheet? I don't think I saw it on the formula sheet posted on the 14B website

I noticed that the equation wasn't on the formula sheet as well, so I think we will have to remember this equation or know how to derive it from the other equations given so that we can use it on the exam.