## 15.61

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

Justin Chu 1G
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### 15.61

For 15.61, is the equation used in the solutions manual a derivation of the Arrhenius equation, and if so, does anyone know how you would go about deriving it? Just wondering since I don't see it on the equations sheet. Thanks!

Lena Nguyen 2H
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### Re: 15.61

It is derived from the Arrhenius equation where one k = Ae^-Ea/RT is divided by k' = Ae^-Ea/RT'. Which k is on top shouldn't matter to get the right answer as long you are consistent with k' matching with T' and k matching with T. By dividing the equations, it gets rid of the A.
k/k' = (e^-Ea/RT)/(e^-Ea/RT')
k/k' = e^(-Ea/RT + Ea/RT')
ln (k/k') = -Ea/RT + Ea/RT'
ln (k/k') = (Ea/R)(1/T' - 1/T)

Lindsay H 2B
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### Re: 15.61

In this question, does it matter which is k and which is k'/which is T vs T' as long as k' and T' correspond to each other?