15.63

Arrhenius Equation:

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Emily Warda 2L
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Joined: Fri Sep 29, 2017 7:06 am
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15.63

Postby Emily Warda 2L » Mon Mar 12, 2018 9:52 pm

The solution states that ln(k’/k)=Ea/R*(1/298K - 1/310K) - 0.59.
What is the significance of the -0.59? Someone previously explained that it is mathematically equivalent to ln(k1/k2) but what is the meaning of it? And why is it being subtracted from the rest of the equation?

Kayla Ikemiya 1E
Posts: 56
Joined: Fri Sep 29, 2017 7:04 am

Re: 15.63

Postby Kayla Ikemiya 1E » Mon Mar 12, 2018 10:27 pm

Why isn't it ln(k2, k1)=Ea/R((1/T1)-(1/T2)? Thats what I used and got the same answer as the solutions manual.


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