## Arrhenius Equation 15.61

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

Cassidy 1G
Posts: 54
Joined: Fri Sep 29, 2017 7:07 am

### Arrhenius Equation 15.61

Could someone explain how we derived this form of the Arrhenius equation in problem 15.61? Usually it is in the form lnk = -Ea/RT + lnA but for this problem we used ln(k'/k) = Ea/R (1/T - 1/T').

Jonathan Tangonan 1E
Posts: 50
Joined: Sat Jul 22, 2017 3:01 am

### Re: Arrhenius Equation 15.61

This equation is derived from the same reaction at different temperatures where the rate constants are different at separate temperatures so:

ln(k1)= lnA - Ea/RT1
ln(k2)= lnA - Ea/RT2

Then we subtract the the equations:

lnk2-lnk1= Ea/R(1/T1-1/T2)

ln(k2/k1)= (Ea/R)(1/T1-1/T2)

Cassidy 1G
Posts: 54
Joined: Fri Sep 29, 2017 7:07 am

### Re: Arrhenius Equation 15.61

Thanks!

Gurkriti Ahluwalia 1K
Posts: 37
Joined: Fri Sep 29, 2017 7:07 am

### Re: Arrhenius Equation 15.61

why do they multiply by the LCF in the solutions manual to obtain t-t'/t times t"