chapter 15 #109

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

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904676178
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Joined: Fri Jun 17, 2016 11:28 am

chapter 15 #109

for question 109 I am confused as to why exactly they used k',
we are given two different temperatures and I used the equation ln k2/k1=Ea/R (1/T1-1/T2), I am wondering why they used k' for k2 in the equation? is it because the temperature is lower for the second temperature given (the first reaction took place at 800 degrees C and now they want use to find the Ea at 700 degrees C) ? meaning it will be k' because it will favor the reverse reaction?

RenuChepuru1L
Posts: 58
Joined: Thu Jul 27, 2017 3:00 am

Re: chapter 15 #109

I don't know if this is right or not but I just treated it like k2 and got the right answer I think they just wrote it a different way, its just a different notation

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