15.67 (6th ed.)

Arrhenius Equation:

Moderators: Chem_Mod, Chem_Admin

Celine Cheng 1H
Posts: 33
Joined: Fri Sep 28, 2018 12:21 am
Been upvoted: 1 time

15.67 (6th ed.)

Postby Celine Cheng 1H » Wed Mar 13, 2019 11:37 pm

In the solutions manual, we see how they start off by showing that 0.6 Ea,uncat = Ea,cat and substituting it into the ratio comparing the rates of the catalyzed and uncatalyzed reactions. Is this step necessary, or can we just directly plug in the activation energies given?

Andrea Zheng 1H
Posts: 61
Joined: Fri Sep 28, 2018 12:26 am

Re: 15.67 (6th ed.)

Postby Andrea Zheng 1H » Thu Mar 14, 2019 12:21 am

I used the method of directly plugging in the values of the Ea into the formula of A*e-Ea/(R*T) to get the ratio of e^x for each of the reactions. I divided the second e^x number (Ea=125) by the first e^x number (Ea=75) and got the factor the k increases by, as A remains constant in both reactions.


Return to “Arrhenius Equation, Activation Energies, Catalysts”

Who is online

Users browsing this forum: No registered users and 1 guest