## Solving for Arrhenius Equation

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

Mya Majewski 1L
Posts: 89
Joined: Fri Sep 25, 2015 3:00 am

### Solving for Arrhenius Equation

In solving for k in the Arrhenius equation k=Ae^-Ea/RT, my value always equals less than one when the answer key says it should be 6 x 10^8 for 6th edition 15.67? How does one solve this on the calculator?

Alyssa Wilson 2A
Posts: 65
Joined: Fri Sep 28, 2018 12:18 am

### Re: Solving for Arrhenius Equation

Maybe try to separate your calculations into solving for -Ea/RT first, then plug that answer into e^(answer). After that try multiplying your value by A, and you should end up with the right rate constant. k (rate constant) is highly dependent on Ea, the activation energy.

MackenziePerillo-1L
Posts: 31
Joined: Fri Sep 28, 2018 12:19 am

### Re: Solving for Arrhenius Equation

I do not know exactly where you are going wrong, but I would make sure that you are using parentheses in the e expression: e^(-Ea/(RT)). I would also write out all of the units of what you are solving to make sure that they all cancel out to get you the desired units of k.