6th edition 15.101

Arrhenius Equation:

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Maddy Mackenzie
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Joined: Fri Sep 28, 2018 12:22 am
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6th edition 15.101

Postby Maddy Mackenzie » Sat Mar 16, 2019 12:34 am

For this question, it asks you for the rate law based on the mechanism of the reactant. I understand why we have to substitute in for the [HClO] because it is an intermediate but the final rate law the solutions has is : rate = (K2)(K1/K1') [ClO-][I-]/[OH-]. Why can we leave OH- in the rate law expression when it too is an intermediate?

Madeline Motamedi 4I
Posts: 62
Joined: Fri Sep 28, 2018 12:23 am

Re: 6th edition 15.101

Postby Madeline Motamedi 4I » Sat Mar 16, 2019 1:25 am

Hi I believe OH isn't an intermediate and its fine to have it in the rate law.


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