k(1)/k(-1)

Arrhenius Equation:

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David Sarkissian 1K
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k(1)/k(-1)

Postby David Sarkissian 1K » Sat Mar 16, 2019 8:23 pm

What does k(1)/k(-1) mean? Why do we use it in our rate law? Mostly I just can't conceptualize what it means or how we find k(-1).

Porus_Karwa_2E
Posts: 72
Joined: Fri Sep 28, 2018 12:24 am

Re: k(1)/k(-1)

Postby Porus_Karwa_2E » Sat Mar 16, 2019 8:38 pm

k(1)/k' =K (equilibrium constant)
k' is the reverse or second process

MichelleRamirez_2F
Posts: 63
Joined: Fri Sep 28, 2018 12:28 am

Re: k(1)/k(-1)

Postby MichelleRamirez_2F » Sat Mar 16, 2019 8:39 pm

k' is referring to the reverse reaction.

Gillian Ward 1F
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Joined: Fri Sep 28, 2018 12:27 am

Re: k(1)/k(-1)

Postby Gillian Ward 1F » Sat Mar 16, 2019 9:00 pm

k is referring to the rate of the forward reaction while k' is referring to the rate of the reverse reaction

Matthew Casillas 1C
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Re: k(1)/k(-1)

Postby Matthew Casillas 1C » Sun Mar 17, 2019 9:05 am

If we want to express both can we use Kc? For example, can we use Kc when doing pre-equilibrium calculations?


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