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k(1)/k(-1)

Posted: Sat Mar 16, 2019 8:23 pm
by David Sarkissian 1K
What does k(1)/k(-1) mean? Why do we use it in our rate law? Mostly I just can't conceptualize what it means or how we find k(-1).

Re: k(1)/k(-1)

Posted: Sat Mar 16, 2019 8:38 pm
by Porus_Karwa_2E
k(1)/k' =K (equilibrium constant)
k' is the reverse or second process

Re: k(1)/k(-1)

Posted: Sat Mar 16, 2019 8:39 pm
by MichelleRamirez_2F
k' is referring to the reverse reaction.

Re: k(1)/k(-1)

Posted: Sat Mar 16, 2019 9:00 pm
by Gillian Ward 1F
k is referring to the rate of the forward reaction while k' is referring to the rate of the reverse reaction

Re: k(1)/k(-1)

Posted: Sun Mar 17, 2019 9:05 am
by Matthew Casillas 1C
If we want to express both can we use Kc? For example, can we use Kc when doing pre-equilibrium calculations?