7D1
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7D1
Could anyone please explain the steps taken in this problem? For example, why did they multiply the temperatures? Did they use the original equation but then canceled out ln[A]?
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Re: 7D1
If I am referring to the same step as you, they multiplied (1/T) by (T'/T') and (1/T') by (T/T) in order to get a common denominator and combine the two expressions
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Re: 7D1
RRahimtoola1I wrote:What equation are they using in this problem?
Honestly I thought that the solution guide answer was confusing.
To solve, use the equation ln(kr2/kr1) = Ea/R(1/T1 - 1/T2), found on page 623 of the textbook.
You use .87 for kr2, .76 for kr1, 8.31•10^-3 for R, 1000 for T1, and 1030 for T2, and solve for Ea.
You should get 38.5667 kJ/mol ≈ 39 kJ/mol.
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Re: 7D1
Jasleen Kahlon wrote:RRahimtoola1I wrote:What equation are they using in this problem?
Honestly I thought that the solution guide answer was confusing.
To solve, use the equation ln(kr2/kr1) = Ea/R(1/T1 - 1/T2), found on page 623 of the textbook.
You use .87 for kr2, .76 for kr1, 8.31•10^-3 for R, 1000 for T1, and 1030 for T2, and solve for Ea.
You should get 38.5667 kJ/mol ≈ 39 kJ/mol.
Thank you so much! I was wondering if I could use that equation, its much simpler.
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