## Pre-Equilibrium Approach

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

Lizette Noriega 1H
Posts: 105
Joined: Wed Sep 18, 2019 12:15 am

### Pre-Equilibrium Approach

Hello,

Can someone clarify the ideas behind the pre-equilibrium approach and explain when it is necessary to use this method? Thanks.

005384106
Posts: 101
Joined: Sat Aug 24, 2019 12:16 am

### Re: Pre-Equilibrium Approach

I also, have a question on this topic. Will we need to come up with each step or will each step be given?

vibha gurunathan 1h
Posts: 51
Joined: Mon Oct 07, 2019 12:15 am

### Re: Pre-Equilibrium Approach

The pre-equilibrium approach says that the intermediate is formed and sustained in a rapid formation reaction and its reverse, and you assume it reaches a sort of equilibrium. Instead, the steady state approach assumes that concentrations of the intermediates are low and don't change. As you don't want intermediates in the overall rate law, you can substitute out for the intermediate if they are present in the slow step. This is b/c the slow step is the rate-determining step.

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