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MCracchiolo 1C
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Joined: Sat Jul 22, 2017 3:00 am


Postby MCracchiolo 1C » Tue Mar 13, 2018 10:23 pm

Would someone be able to explain why 15.67 uses the ratio of activation energies? i.e. How would I have known to substitute Ea(cat) without looking at the solution manual?

Curtis Tam 1J
Posts: 105
Joined: Thu Jul 13, 2017 3:00 am

Re: 15.67

Postby Curtis Tam 1J » Wed Mar 14, 2018 10:11 am

They're using the ratios to see how the rate changes with respect to activation energy. I believe you could have plugged in the actual values given in the problem but simply keeping the Ea as a variable makes the calculation easier.

Ahmed Mahmood 4D
Posts: 72
Joined: Fri Sep 28, 2018 12:28 am

Re: 15.67

Postby Ahmed Mahmood 4D » Fri Mar 15, 2019 1:44 am

Think about it like this: You have two reaction rates, and you want to compare how the factor is affected by the addition of a catalyst. You know that adding a catalyst changes the activation energy; you know that changing the activation energy changes the reaction rate; you know the formula for the reaction rate. Therefore, in order to calculate the factor by which adding a catalyst changes the reaction rate, you must calculate the ratio of the catalyzed/uncatalyzed reaction rates (Aexp(-Ea[cat]/RT)/Aexp(-Ea[uncat]/RT)). A cancels out.

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