## Catalyst and equilibrium constant

$V_{0} = \frac{V_{max}[S]}{K_{M} + [S]}; K_{M} = \frac{[E][S]}{[ES]}$

Peter Dis1G
Posts: 97
Joined: Fri Sep 29, 2017 7:04 am

### Catalyst and equilibrium constant

On chapter 15.14 it says "a catalyst has no effect on the equilibrium composition. both forward and reverse reactions are accelerated on the catalyzed path,leaving th equilibrium constant unchanged." Does it mean the catalyst has no effect on K?

Nha Dang 2I
Posts: 53
Joined: Fri Sep 29, 2017 7:07 am

### Re: Catalyst and equilibrium constant

Yes, K doesn't change when a catalyst is added.

Rana YT 2L
Posts: 49
Joined: Thu Jul 27, 2017 3:01 am

### Re: Catalyst and equilibrium constant

the equilibrium constant does not change but the k that is the rate constant does change

Katelyn B 2E
Posts: 29
Joined: Fri Sep 29, 2017 7:05 am

### Re: Catalyst and equilibrium constant

A catalyst won't affect the equilibrium constant k, which is the ratio of products to reactants when a reversible chemical reaction reaches equilibrium at a given temperature. However, because catalysts increase the rate of a reaction, it can affect rate constant k. Be cognizant of which k constant is involved in the problem.