## Poison a Catalyst

$V_{0} = \frac{V_{max}[S]}{K_{M} + [S]}; K_{M} = \frac{[E][S]}{[ES]}$

ShravanPatel2B
Posts: 100
Joined: Fri Aug 30, 2019 12:18 am

### Poison a Catalyst

What exactly does it mean to poison a catalyst? Does this play a role when solving problems or answering any questions conceptually?

Jack Riley 4f
Posts: 100
Joined: Sat Aug 24, 2019 12:17 am

### Re: Poison a Catalyst

It may matter conceptually, but I doubt quantitatively. Poisoning a catalyst is to cause it to lose its function.

Zaynab Hashm 2I
Posts: 110
Joined: Wed Sep 11, 2019 12:15 am
Been upvoted: 1 time

### Re: Poison a Catalyst

it's important to know that it means a catalyst is no longer active and cannot function in speeding up a reaction; this could occur due to exposure to certain chemicals

Posts: 125
Joined: Sat Aug 17, 2019 12:17 am

### Re: Poison a Catalyst

ShravanPatel2B wrote:What exactly does it mean to poison a catalyst? Does this play a role when solving problems or answering any questions conceptually?

In the textbook, I believe that they mentioned poisoning a catalyst just as an example of how if a poison is on the catalyst of a reaction, for example, an enzyme, and is on the active site, the substrate cannot attach itself, and thus the catalyst is useless.