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Pre Equilibruim Approach

Posted: Thu Feb 18, 2016 10:17 pm
by priyasihota3c
What is the difference in the pre equilibrium approach and the steady-state approach?

Re: Pre Equilibruim Approach

Posted: Fri Feb 19, 2016 5:07 pm
by Katherine Jabba 2H
The pre-equilibirum approach uses a psuedo-equilibrium situation where one of the steps of the reaction is said to be at equilibrium and set equal to K, the equilibirum constant. This equation involving K is then manipulated and subsituted into the other reaction rate equation, so that the the reaction rate equation of the steps ends up looking like the observed reaction rate. It is a lot simpler method than the steady-state approach, which involves calculus.

Re: Pre Equilibruim Approach

Posted: Tue Mar 12, 2019 4:20 pm
by Jeremiah Hutauruk
involves k

Re: Pre Equilibruim Approach

Posted: Tue Mar 12, 2019 4:47 pm
by Vicky Lu 1L
The pre-equilibrium approach starts with has a fast elementary step followed by a slow elementary step. With the pre-equilibrium approach, we can't have intermediates between the fast and slow in the rate law. This approach also doesn't factor in account the reverse reaction that is occurring in the fast reaction, therefore, we want to substitute a term in for the intermediate step to have an overall rate law that is based on the slow step and does not include in intermediates.

Re: Pre Equilibruim Approach

Posted: Wed Mar 13, 2019 9:16 pm
by haleyervin7
Do you need the observed rate to be given for this approach?

Re: Pre Equilibruim Approach

Posted: Thu Mar 14, 2019 1:05 am
by Destiny Diaz 4D
would we be specifically asked to solve using the pre equilibrium approach?

Re: Pre Equilibruim Approach

Posted: Thu Mar 14, 2019 1:05 am
by Destiny Diaz 4D
Destiny Diaz 4D wrote:would we be specifically asked to solve using the pre equilibrium approach?

I feel like based on the question and what is given you would determine this, but I wanted to ask to be sure?