Midterm 2a

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Ghadir Seder 1G
Posts: 134
Joined: Sat Sep 14, 2019 12:17 am

Midterm 2a

Postby Ghadir Seder 1G » Fri Nov 29, 2019 3:04 pm

Can anyone explain how for question 2a frequency is equal to E/H? Im referencing E=hc and c=lambda(v) and I couldn't find a way to manipulate them to get v=e/h. Thank you!

nicolely2F
Posts: 149
Joined: Sat Sep 14, 2019 12:17 am

Re: Midterm 2a

Postby nicolely2F » Fri Nov 29, 2019 3:17 pm

You don't have to use the combined equation -- you can do first E = h.v and then c = lambda.v (when using E=h.v remember to convert kJ to J and find the energy per atom, as the work function given is per mol). But if you're interested in using the combined equation, simply single out v in the second equation to obtain v = c/lambda, then plug that into E = h.v to obtain E = (h.c)/lambda.

Ghadir Seder 1G
Posts: 134
Joined: Sat Sep 14, 2019 12:17 am

Re: Midterm 2a

Postby Ghadir Seder 1G » Fri Nov 29, 2019 4:39 pm

I get that you can get E=h.c/lambda but lavelle used v=E/H ... How can i get to the equation he used ?

CynthiaLy4F
Posts: 103
Joined: Sat Jul 20, 2019 12:16 am

Re: Midterm 2a

Postby CynthiaLy4F » Fri Nov 29, 2019 5:02 pm

I think Lavelle got the equation v=E/h by just manipulating the equation E=h*v.

Ghadir Seder 1G
Posts: 134
Joined: Sat Sep 14, 2019 12:17 am

Re: Midterm 2a

Postby Ghadir Seder 1G » Fri Nov 29, 2019 5:34 pm

Ohhhh i see it now, thanks for the help!


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