Midterm 2a
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Midterm 2a
Can anyone explain how for question 2a frequency is equal to E/H? Im referencing E=hc and c=lambda(v) and I couldn't find a way to manipulate them to get v=e/h. Thank you!
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Re: Midterm 2a
You don't have to use the combined equation -- you can do first E = h.v and then c = lambda.v (when using E=h.v remember to convert kJ to J and find the energy per atom, as the work function given is per mol). But if you're interested in using the combined equation, simply single out v in the second equation to obtain v = c/lambda, then plug that into E = h.v to obtain E = (h.c)/lambda.
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Re: Midterm 2a
I get that you can get E=h.c/lambda but lavelle used v=E/H ... How can i get to the equation he used ?
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