Q6A.23

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Meghan Krushena 2E
Posts: 102
Joined: Wed Sep 30, 2020 10:10 pm

Q6A.23

Postby Meghan Krushena 2E » Wed Mar 10, 2021 11:52 pm

Could someone explain how you know that [Ba(OH)2] is equal to [Ba2+] and [OH-] is equal to 2x[Ba(OH)2]? I understand its 2x because there are 2 moles of OH- formed in the reaction, but how are these concentrations determined?
Here is the question for reference:
Calculate the molar concentration of [Ba(OH)2] and the molar concentrations of [Ba2+] and [OH-] and [H3O+] in an aqueous solution that contains 0.43 g of [Ba(OH)2] in 0.100 L of solution.

Meghan Krushena 2E
Posts: 102
Joined: Wed Sep 30, 2020 10:10 pm

Re: Q6A.23

Postby Meghan Krushena 2E » Thu Mar 11, 2021 12:09 am

**meant to post in 14B group, not for 14A please ignore


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