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The first thing I did was I wrote out the reaction that would take place for the acid CH3COOH. When this is added to water, you end up with H30+ and CH3COO- in the products. Since the solution is at pH=6 which is slightly acidic, we know that there are more products in the solution because H3O+ is on the products side. Therefore, the net charge would be -1 because CH3COO- is present in a larger concentration in the solution.
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