Week 10 Review Question

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Julia Holsinger_1A
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Joined: Tue Feb 26, 2019 12:16 am

Week 10 Review Question

Postby Julia Holsinger_1A » Thu Mar 12, 2020 9:59 am

From Lavelle's Week 10 Review slides that he posted, On the first slide, how do you get the change in molar concentration? I am confused with how 0.075 and 0.225 were calculated.

Myka G 1l
Posts: 100
Joined: Fri Aug 30, 2019 12:17 am

Re: Week 10 Review Question

Postby Myka G 1l » Thu Mar 12, 2020 10:06 am

.0150 mol NH3 was formed, which means that half that amount of N2(.075) decreased. This occurs because the stoichiometric coefficient of NH3 is 2 and the coefficient for N2 is 1. The same goes for the H2 but it decreases by 1/3 of the amount of NH3 formed.

Tanmay Singhal 1H
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Joined: Sat Jul 20, 2019 12:16 am

Re: Week 10 Review Question

Postby Tanmay Singhal 1H » Thu Mar 12, 2020 1:11 pm

you have to use the ratios as well as the actual numbers and do stoichiometry

Maya Gollamudi 1G
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Joined: Thu Jul 25, 2019 12:15 am

Re: Week 10 Review Question

Postby Maya Gollamudi 1G » Sat Mar 14, 2020 8:25 am

We know that the equilibrium concentration of NH3 is 0.150 M, so using stoichiometric ratios and an ICE chart we can determine that the concentrations of N2 and H2 decrease by 0.075 M and 0.225 M, respectively.

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Joined: Sat Sep 07, 2019 12:16 am

Re: Week 10 Review Question

Postby Philip » Sat Mar 14, 2020 8:28 am

Using the stoichiometric ratios and creating an ice table you should be able to calculate the molar concentrations

Dan M -3E
Posts: 101
Joined: Wed Sep 18, 2019 12:19 am

Re: Week 10 Review Question

Postby Dan M -3E » Sat Mar 14, 2020 2:17 pm

By knowing the change in one of the reactants/products over the reaction, we can use the stoichiometric ratio to calculate the change for the others.

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