Hello,
I'm stuck on the second part of problem 6 from the weeks 2, 3, and 4 hw. I got the right work function, but I am confused on how to calculate the maximum number of electrons that could be ejected from the metal. Can someone explain?
HW problem 6
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isaiah_granados_2l
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Re: HW problem 6
Hi!
The work function descries the threshold that it takes for one electron to be ejected from the metal. The units are J/photon and we can convert from Joules/Photon to electron. We know that a photon is 1/e^-. So when we divide J/J/e we get joules that cross out and are left with electron. So you can divide your total energy in joules by the work value in joules/photon to get the number of electrons. Hope that helps
The work function descries the threshold that it takes for one electron to be ejected from the metal. The units are J/photon and we can convert from Joules/Photon to electron. We know that a photon is 1/e^-. So when we divide J/J/e we get joules that cross out and are left with electron. So you can divide your total energy in joules by the work value in joules/photon to get the number of electrons. Hope that helps
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