Photoelectric effect [ENDORSED]

[Kevin Hernandez 3A]

This and the following question relates to the same metal used in a series of photoelectric experiments.

A. If 3.607 x 10-19 J is required to remove an electron with zero kinetic energy from a metal surface, what would be the longest wavelength light that could do this?

a) KE= energy of photon - work function
4.200x10^-19= Ep - 3.607x10^-19
Ep= 7.807x10^-19

b) Ep= hv
7.807x10^-19= 6.63x10^-34(v)
v=1.18x10^15

c)c=wavelenght(v)
3.00x10^18=(w)1.18x10^15
w=
How do you convert m to nm??

[Kaileigh Yang 2I]

1 nm = 10^-9 m

[Camille 4I]

Where did you get the number 4.200x10^-19 from?

[ramiro_romero]

You convert from nm to m by mnultiplying by 10^-9. However, I am much more concerned as to how you got your value for the energy of a photon. Your kinetic energy is specified at a value of zero. You should've gotten the work function equal to the energy of the photon (since there's no excess energy).

Ep = (3.607 x 10^-19)

[ShreyaKannan1B]

Where did you get the number 4.200x10^-19 from?

Yeah I don't get that either.

[Charlene D 3H]

Where did you get the number 4.200x10^-19 from?

Yeah I don't get that either.

I believe he got that number from the next question (#32) that's related to this one. However the problem can be solved without this information.

[Giselle_zamora_1L]

for part a, would you use some form of variation id c=(lambda)(frequency) ?

This and the following question relates to the same metal used in a series of photoelectric experiments.

A. If 3.607 x 10-19 J is required to remove an electron with zero kinetic energy from a metal surface, what would be the longest wavelength light that could do this?

a) KE= energy of photon - work function
4.200x10^-19= Ep - 3.607x10^-19
Ep= 7.807x10^-19

b) Ep= hv
7.807x10^-19= 6.63x10^-34(v)
v=1.18x10^15

c)c=wavelenght(v)
3.00x10^18=(w)1.18x10^15
w=
How do you convert m to nm??