Post Module #24

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Mariane Sanchez 1E
Posts: 57
Joined: Fri Sep 29, 2017 7:07 am

Post Module #24

Postby Mariane Sanchez 1E » Mon Oct 16, 2017 7:59 pm

Hey all, can someone tell me what the right answer and why fro #24? I tried answering visible light but it was incorrect.
Thanks!
In photoelectric experiments, typically what part of the electromagnetic spectrum is the incoming light?

A. Ultraviolet

B. Infrared

C. Visible light

D. Gamma rays

E. None of the above

Gianna Apoderado 1B
Posts: 57
Joined: Fri Sep 29, 2017 7:04 am

Re: Post Module #24

Postby Gianna Apoderado 1B » Mon Oct 16, 2017 8:28 pm

I believe the answer is UV! If I'm not mistaken, ultraviolet radiation is used because it has a short wavelength (high frequency), which means it has a higher energy per photon (E=hv). Even with low intensity light, it can eject electrons from the surface.

Glendy Gonzalez 1A
Posts: 52
Joined: Fri Sep 29, 2017 7:07 am

Re: Post Module #24

Postby Glendy Gonzalez 1A » Sun Oct 22, 2017 1:42 pm

The answer is Ultraviolet light. I think that one of the reason is because ultraviolet light has a relatively small wavelength, which results in high frequency. As we have learned, high frequency results in high energy. Therefore, more electrons were able to be transmitted under ultraviolet light. Due to this relationship, most elements have threshold frequencies in the UV region.

104922499 1F
Posts: 53
Joined: Fri Sep 29, 2017 7:04 am

Re: Post Module #24

Postby 104922499 1F » Sun Oct 22, 2017 3:52 pm

The answer is UV because that part of the spectrum has a small wavelength with high frequency. And we know that high frequency allows for electrons to be ejected from the surface.


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