Photoelectric Effect Post Module [ENDORSED]

[SammiOrsini_1B]

28. Light hits a sodium metal surface and the velocity of the ejected electron is 6.61 x 105 m.s-1. The work function for sodium is 150.6 kJ.mol-1.
Answer the following three questions.
A. What is the kinetic energy of the ejected electron?

D. 1.99 x 10-19 J
I figures out that the kinetic energy is 1.99 x 10^-19 J however i cant figure out the next parts.

B. How much energy is required to remove an electron from one sodium atom?

A. 2.501 x 10-22 J

B. 1.506 x 105 J

C. 2.501 x 10-19 J

D. 9.069 x 1028 J

E. None of the above

30. C. What is the frequency of the incident light on the sodium metal surface?

A. 3.01 x 1014 Hz

B. 2.27 x 1038 Hz

C. 4.54 x 1058 Hz

D. 6.78 x 1014 Hz

E. None of the above

[Susu Le 1F]

B) The amount of energy required to remove an electron from one sodium atom is equal to the work function of sodium that is given in the question. Therefore, just convert the 150.6 kJ to J, and you would result in 1.506 x 10^5 J.

C) The energy of the photon of light that is hitting the sodium surface is equal to the work function plus the kinetic energy of the electron. So to get the frequency of the incident light, add the work function and kinetic energy and then plug it into E in the equation E=hv, and solve for v.

[SammiOrsini_1B]

Okay thank you! On B i was confused because i got the same answer as you but the system said i was incorrect. Thank you!