Question 1.33, part b

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Toru Fiberesima 1L
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Joined: Fri Apr 06, 2018 11:02 am

Question 1.33, part b

Postby Toru Fiberesima 1L » Thu Apr 26, 2018 5:22 pm

The velocity of an electron that is emitted from a metallic surface by a photon is 3.6x10^3 km/s. No electrons are emitted from the surface of the metal until the frequency of the radiation reaches 2.50x10^16Hz. How much energy is required to remove the electron from the metal?

I know you eventually have to find the work function by subtracting kinetic energy of the electron (which I have calculated from the velocity) from the E of the photon but how do you get the other two values. I also have the wavelength from part a.

Tiffany Chen 1A
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Joined: Fri Apr 06, 2018 11:02 am
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Re: Question 1.33, part b

Postby Tiffany Chen 1A » Thu Apr 26, 2018 5:43 pm

I think you can just use E=hv to solve for the threshold energy. So E=(6.626*10^-34)(2.50*10^16) should give you the correct answer.


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