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Question 1.33, part b

Posted: Thu Apr 26, 2018 5:22 pm
by Toru Fiberesima 1L
The velocity of an electron that is emitted from a metallic surface by a photon is 3.6x10^3 km/s. No electrons are emitted from the surface of the metal until the frequency of the radiation reaches 2.50x10^16Hz. How much energy is required to remove the electron from the metal?

I know you eventually have to find the work function by subtracting kinetic energy of the electron (which I have calculated from the velocity) from the E of the photon but how do you get the other two values. I also have the wavelength from part a.

Re: Question 1.33, part b

Posted: Thu Apr 26, 2018 5:43 pm
by Tiffany Chen 1A
I think you can just use E=hv to solve for the threshold energy. So E=(6.626*10^-34)(2.50*10^16) should give you the correct answer.