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Posted: Sat May 05, 2018 11:59 pm
by Melissa_Aguirre1J
1.34 The work function for chromium metal is 4.37 eV. What wavelength of radiation must be used to eject electrons with a velocity of 1.5  103 kms1?

Re: 1.34

Posted: Sun May 06, 2018 3:33 am
by Susu Le 1F
Energy of the photon of radiation=work function+kinetic energy of the electron
1) Convert 4.37 eV to J using 1 eV=1.602x10-19 J. This is the work function.
2) Find the kinetic energy of the electron by using Ek=1/2*m*v^2.
3) Add the work function and the Ek(kinetic energy) together to get the energy of the photon.
4) Use E=hc/lambda to find lambda (the wavelength of the light).

Re: 1.34

Posted: Thu Jun 14, 2018 1:01 pm
by 105012653 1F
I did the steps but I still got something different...