1B.15 Part C

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Rachel Yoo 1F
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Joined: Fri Sep 28, 2018 12:24 am

1B.15 Part C

Postby Rachel Yoo 1F » Sun Oct 14, 2018 10:55 am

The velocity of an electron that is emitted from a metallic surface by a photon is 3.6*10^3 km*s^-1.
part c. what is the wavelength of the radiation that caused photoejection of the electron?
I got part a and b but I'm not really sure how to do this part but I tried both the equations lambda=c/v and lambda=ch/(work function) but I didn't get the answer on the back of the book

Maya_Peterson1C
Posts: 62
Joined: Fri Sep 28, 2018 12:28 am

Re: 1B.15 Part C

Postby Maya_Peterson1C » Sun Oct 14, 2018 11:52 am

I don't see a question 1B.15 in the textbook. Is it at the end of the chapter?

Jonathan Omens 1K
Posts: 60
Joined: Fri Sep 28, 2018 12:15 am

Re: 1B.15 Part C

Postby Jonathan Omens 1K » Sun Oct 14, 2018 9:06 pm

Use the equation to find the energy of the incoming radiation: . The velocity of the ejected electron is given and the mass of the electron is in the list of constants, so you can calculate (kinetic energy of electron) using . In part (b) you calculated the work function (). Plug these two values into the equation to get .
Now that you have the energy of the radiation (photon), calculate its wavelength () using the functions and (or just combine them to make ).


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