1B.15 Part C

Moderators: Chem_Mod, Chem_Admin

Rachel Yoo 1F
Posts: 65
Joined: Fri Sep 28, 2018 12:24 am

1B.15 Part C

Postby Rachel Yoo 1F » Sun Oct 14, 2018 10:55 am

The velocity of an electron that is emitted from a metallic surface by a photon is 3.6*10^3 km*s^-1.
part c. what is the wavelength of the radiation that caused photoejection of the electron?
I got part a and b but I'm not really sure how to do this part but I tried both the equations lambda=c/v and lambda=ch/(work function) but I didn't get the answer on the back of the book

Posts: 62
Joined: Fri Sep 28, 2018 12:28 am

Re: 1B.15 Part C

Postby Maya_Peterson1C » Sun Oct 14, 2018 11:52 am

I don't see a question 1B.15 in the textbook. Is it at the end of the chapter?

Jonathan Omens 1K
Posts: 60
Joined: Fri Sep 28, 2018 12:15 am

Re: 1B.15 Part C

Postby Jonathan Omens 1K » Sun Oct 14, 2018 9:06 pm

Use the equation to find the energy of the incoming radiation: . The velocity of the ejected electron is given and the mass of the electron is in the list of constants, so you can calculate (kinetic energy of electron) using . In part (b) you calculated the work function (). Plug these two values into the equation to get .
Now that you have the energy of the radiation (photon), calculate its wavelength () using the functions and (or just combine them to make ).

Return to “Photoelectric Effect”

Who is online

Users browsing this forum: No registered users and 3 guests