Question 1.33 (sixth edition)

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904901860
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Joined: Mon Jan 08, 2018 8:16 am

Question 1.33 (sixth edition)

Postby 904901860 » Tue Oct 23, 2018 5:02 pm

I was wondering if we are supposed to use the answer we get from a) to solve b) or if we're supposed to approach the problem in a different way? Also I don't know how to go about c) either.


(b) No electrons are
emitted from the surface of the metal until the frequency of
the radiation reaches 2.50 " 1016 Hz. How much energy
is required to remove the electron from the metal surface?
(c) What is the wavelength of the radiation that caused
photoejection of the electron?

Fayez Kanj
Posts: 62
Joined: Fri Sep 28, 2018 12:18 am
Been upvoted: 1 time

Re: Question 1.33 (sixth edition)

Postby Fayez Kanj » Tue Oct 23, 2018 5:53 pm

Hi!

So for b), since you have the frequency "v" you can calculate the energy E using E=hv.

For c), since you have the frequency "v" you can calculate the wavelength of the light "lambda" using C= lambda/wavelength x frequency

Hope that helps :)

904901860
Posts: 24
Joined: Mon Jan 08, 2018 8:16 am

Re: Question 1.33 (sixth edition)

Postby 904901860 » Tue Oct 23, 2018 6:50 pm

Thank you so much!


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