Photoelectric Experiment - Chem Test 2

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Krisdylle Repollo 4H
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Joined: Fri Sep 28, 2018 12:28 am

Photoelectric Experiment - Chem Test 2

Postby Krisdylle Repollo 4H » Fri Nov 02, 2018 10:37 am

4. In an X-ray photoelectron experiment, lead metal is irradiated with X-ray light.
Part A: The intensity of ejected electrons is plotted as a function of their velocity, as shown in the graph below. Calculate the total kinetic energy in 5 mol of ejected electrons.

What does it mean by “5 mol of ejected electrons”? How do we find the mol of ejected electrons? Also, when using the E(k) equation for this problem, is the mass that we plug in the mass of Pb or the mass of the electron?

Megan Gianna Uy 3L
Posts: 30
Joined: Fri Sep 28, 2018 12:26 am

Re: Photoelectric Experiment - Chem Test 2

Postby Megan Gianna Uy 3L » Fri Nov 02, 2018 11:29 am

To find 5 moles of ejected electron, you would multiply your answer by plancks constant and multiply that by 5.

Adrian C 1D
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Joined: Fri Sep 28, 2018 12:19 am

Re: Photoelectric Experiment - Chem Test 2

Postby Adrian C 1D » Fri Nov 02, 2018 6:07 pm

You would use the mass of the electron in the Ek equation since it is an electron being ejected, not a lead atom.

Duby3L
Posts: 72
Joined: Fri Sep 28, 2018 12:26 am

Re: Photoelectric Experiment - Chem Test 2

Postby Duby3L » Fri Nov 02, 2018 6:39 pm

Was the kinetic energy 5.5x^10^6?


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