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Posted: Thu Oct 10, 2019 11:58 pm
Hello. I forgot the reasoning behind why light with shorter wavelengths results in more electron emissions. Can someone please help? :)
Posted: Fri Oct 11, 2019 12:35 am
You can think of it in terms of 3 equations: c= λv , E = hv , and E = hc/λ
As you can see, if you isolate v in the first equation, you get v = c/λ which the 3rd equation is derived on. Now focusing on the 2nd and 3rd equation, it clearly shows that Energy is directly proportional to the frequency of the light while energy is inversely proportional to the wavelength of light. The energy represents the amount of work necessary, whether it be the threshold of a certain metal or the amount of energy stored in the photon, that will eventually be emitted as an electron. No matter what value we assign the threshold of the metal, the greater quantity of energy will equate to a greater amount of emissions.
Posted: Fri Oct 11, 2019 1:10 am
The intensity of the photons hitting the metal surface is not as important as the frequency of the photons hitting the metal. Higher energy light results from the increased frequency, in other words a shorter wavelength, because all of these variables have a proportional relationship to one another.
Posted: Fri Oct 11, 2019 5:32 am
What is the relationship between wavelength, frequency and energy?
Posted: Fri Oct 11, 2019 6:53 am
Higher Frequency = Higher Energy, Shorter wavelength = Higher Frequency
Posted: Fri Oct 11, 2019 9:23 am
Could someone also explain if there is any correlation between amplitude and frequency?
Posted: Fri Oct 11, 2019 4:47 pm
There is no correlation between amplitude and frequency. Amplitude is just how high or low a wave can go, which exists independently of the frequency of a wave, which is the number of waves in a given time.
Posted: Fri Oct 11, 2019 5:51 pm
Amplitude has to do with intensity. The higher the amplitude, the more intense the light is and the lower the amplitude, the less intense the light it.
Posted: Fri Oct 11, 2019 5:53 pm
Amplitude, or intensity, for waves are measured by the height of the waves from their base to their peak. However, if light is regarded as a photon, amplitude, or intensity, is simply the number of photon particles emitted. That's why light with higher intensity resulted in more electron emissions but electrons with the same kinetic energy during the photoelectric experiment.