Estimating the uncertainty in the location or speed of a particle

[Jessica Esparza 2H]

HW Question 1B.5
How would you go about answering the following question? I'm having trouble beginning it.

The y-ray photons emitted by the nuclear decay of a technetium-99 atom used in radiopharmaceuticals have an energy of 140.511 keV. Calculate the wavelength of these y-rays.

[Christine Honda 2I]

You will need to use a combined version of these two equations
and E=hv and c=λv
1st we are given KeV units but we need to convert that to eV then to joules since energy is measured in joules.
Kilo means 1000 of whatever unit is used. Therefore we multiply 140.511*10^3
Also the conversion factor for eV to joules is 1eV=1.6022*10^{-19} J

E= (140.511 x 10^3 eV)(1.6022 x 10^-19 J/eV) = 2.251 x 10^-14 J
Then we can combine the equations in order to get the wavelength
equation.

The wavelength equation becomes
λ=hc/E

Therefore,
(6.626 x 10^-34 J*s)(2.99792 x 10^8 m/s)/(2.251 x 10^-14J) = 8.824 x 10^-12= 883 nm