3 posts • Page 1 of 1
In a key concept we went over in class that states the above equations (relating to the Photoelectric Effect) illustrate the conservation of energy unless E (photon) is greater than or equal to E (energy remove e-) then e- is not emitted even for high intensity light. Can someone explain this and possibly give an example?
Metal needs a certain energy of light in order to remove electrons from its surface. The higher the frequency, the higher the energy. The energy of the light has to exceed a threshold energy needed to remove electrons from the surface of the metal. Once the threshold is exceeded, one electron will be emitted per one photon. Increasing the intensity of the light, once this threshold is reached, will increase the amount of electrons emitted because the amount of photons increases with intensity increase.
I believe this concept refers to the particle properties of light. If light was just a wave then increasing the intensity of light should eject electrons, but that wasn't what happened in experiments. Energy has to be high enough per photon to induce electron removal from a metal surface. Increasing the frequency gives way to photons being able to remove electrons from the metal surface, in which one photon interacts with one electron.
Who is online
Users browsing this forum: No registered users and 1 guest