## Electrons and High Intensity Light

Kimberly Bauer 4E
Posts: 51
Joined: Thu Jul 25, 2019 12:17 am

### Electrons and High Intensity Light

In a key concept we went over in class that states the above equations (relating to the Photoelectric Effect) illustrate the conservation of energy unless E (photon) is greater than or equal to E (energy remove e-) then e- is not emitted even for high intensity light. Can someone explain this and possibly give an example?

DTingey_1C
Posts: 55
Joined: Fri Aug 30, 2019 12:16 am

### Re: Electrons and High Intensity Light

Metal needs a certain energy of light in order to remove electrons from its surface. The higher the frequency, the higher the energy. The energy of the light has to exceed a threshold energy needed to remove electrons from the surface of the metal. Once the threshold is exceeded, one electron will be emitted per one photon. Increasing the intensity of the light, once this threshold is reached, will increase the amount of electrons emitted because the amount of photons increases with intensity increase.

Indy Bui 1l
Posts: 99
Joined: Sat Sep 07, 2019 12:19 am

### Re: Electrons and High Intensity Light

I believe this concept refers to the particle properties of light. If light was just a wave then increasing the intensity of light should eject electrons, but that wasn't what happened in experiments. Energy has to be high enough per photon to induce electron removal from a metal surface. Increasing the frequency gives way to photons being able to remove electrons from the metal surface, in which one photon interacts with one electron.