Energy of electron
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Energy of electron
1B.7 is asking for the energy emitted by a sodium atom when it generates a photon and for the energy of 5.00 mg of sodium emitting light. Do I think of the excited sodium atom as a photon in this problem? As in the formula E=hv applies to this question, not the kinetic energy of an electron. Then, I would apply the energy of photon formula to the molar amount of sodium to solve the rest of the question?
Re: Energy of electron
Yes you should use the energy of photon formula, so for part A you would convert the given wavelength to meters in order to plug it into the equation E=hc/lambda. Then for part B you convert the mass of the sodium atoms into atoms of sodium through dimensional analysis. You would turn the mg to grams, then the grams to mols, then the mols to atoms using avagadros numbers. Multiply the amount of atoms by the amount of energy you calculated in part A to get your answer of 44.1 J. Lastly for part C take your mols of Na and convert to atoms of Na using avagadros numbers again and multiply your atoms by the energy you found in part A, this will give you 2.03x10^5 J.
Re: Energy of electron
Yes! The equation E=hv can be applied because it corresponds to the energy of one photon. The de Broglie equation is used for the energy of one particle/atom.
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