Can anyone define/explain the photoelectric effect in simple terms?
Also can anyone explain the equation E(photon)- E(energy remove e-) = E(excess) = Ek (e-)
Photoelectric Effect
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Re: Photoelectric Effect
In simple terms, the energy of a photon + the energy required to remove an electron = the energy of the removed electron (the excess/what remains). Hope this helps!
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Re: Photoelectric Effect
The photoelectric effect is the phenomenon where light of certain frequencies projected onto a metal causes electrons to be ejected from the metal.
As for the equation, every metal has a certain energy threshold that each photon must meet in order to eject an electron. This energy threshold is denoted by E (energy remove e-). Any additional energy of the photon above that threshold will be transferred to the electron in the form of kinetic energy, which is denoted by Ek (e-). You can determine the amount of additional energy available to be transferred to the electron in the form of kinetic energy, Ek (e-), by subtracting the energy threshold per photon required to remove an electron, E (energy remove e-), from the actual energy of the photon, E (photon). I hope this helps!
As for the equation, every metal has a certain energy threshold that each photon must meet in order to eject an electron. This energy threshold is denoted by E (energy remove e-). Any additional energy of the photon above that threshold will be transferred to the electron in the form of kinetic energy, which is denoted by Ek (e-). You can determine the amount of additional energy available to be transferred to the electron in the form of kinetic energy, Ek (e-), by subtracting the energy threshold per photon required to remove an electron, E (energy remove e-), from the actual energy of the photon, E (photon). I hope this helps!
Re: Photoelectric Effect
What exactly are the "unexpected outcomes" that make the photoelectric effect?
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Re: Photoelectric Effect
I'm not quite sure if this is what you were referring to, but the unexpected outcome that was observed during the photoelectric experiment was that no electrons were ejected even when a higher intensity light was used. That led scientists to decrease the wavelength of light to the UV region and that's when they observed electrons ejected (even when they were using a lower intensity light). That led to the eventual conclusion that the energy of the photon must be greater than or equal to the energy needed to eject the electron from the metal, and that can be accomplished using a shorter wavelength light as opposed to higher intensity light (which merely increased the number of photons hitting the metal surface rather than changing their actual energy).
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Re: Photoelectric Effect
Regarding the equation, you could also think about it in terms of the Law of Conservation of Energy, ie, the total energy of the incoming photon (E photon) = the energy that is used to remove the electron from the metal (E energy to remove e-) plus the energy that is left over (E excess), which is transferred to the electron (Ek e-). You can represent this by rewriting the equation:
E(photon) = E(energy to remove e-) + E(excess). Keep in mind E(excess) is the same as Ek (e-) since the excess energy is transferred to the electron.
Hope this helps.
E(photon) = E(energy to remove e-) + E(excess). Keep in mind E(excess) is the same as Ek (e-) since the excess energy is transferred to the electron.
Hope this helps.
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