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For #32, you use the information given in #31 as well, since it states that both problems refer to the same metal. In #31, it tells us that 3.607 x 10^-19 J is required to remove an electron from a metal surface, so this is our work function. In #32, it tells us that the kinetic energy is 4.200 x 10^-19 J. Now you can use the Ephoton-work function=Ek equation to find the energy of the photon. To find the wavelength, set the energy you found equal to hc/lambda (aka hv) and solve for lambda.
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