Exercise 1B9

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Sandra Kim 2B
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Joined: Wed Sep 30, 2020 9:50 pm

Exercise 1B9

Postby Sandra Kim 2B » Sun Oct 25, 2020 6:22 pm

I saw in the student solution manual for exercise 1B9 that they used the function: E=hcλ^-1 to find how many photons are generated. I just want to know how they got this equation to solve the problem.

Melody Haratian 2J
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Re: Exercise 1B9

Postby Melody Haratian 2J » Sun Oct 25, 2020 6:28 pm

Hi! They derived that equation by using these two equations:
1. E= hv
2. c = λv
you can find what frequency is equal to from the speed of light equation.
Rearrange c = λv so that it becomes v = c/λ . Then, you can plug this into the v of the energy of a photon equation. So E = hv will become E = hc/λ , by replacing v with c/λ ( which it is equal to).

Ralph Zhang 2L
Posts: 53
Joined: Wed Sep 30, 2020 9:55 pm

Re: Exercise 1B9

Postby Ralph Zhang 2L » Sun Oct 25, 2020 6:30 pm

I suggest watching the photoelectric effect video module in the class page, the professor specifically goes over that equation.

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