the question states:
A violet line is observed at 434.0 nm in the spectrum of atomic hydrogen. Determine the values of "n" for the beginning and ending energy levels of the electron during the emission of energy that leads to this spectral line.
n2= ?
n1=?
I know n1 is 2 but I'm having trouble getting n2.
Sapling HW #11
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Re: Sapling HW #11
To find n2, convert the wavelength into meters, and then use the equation
to find the frequency. Once you find the frequency, you can use the Rydberg equation. Input the frequency, Rydberg's constant, and the final energy level into
, and you should be able to find the initial energy level.
Hope this helps!
Hope this helps!
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Re: Sapling HW #11
The above post is correct. You first need to covert 434.0 nm to meters, and solve for frequency using v=(c)/(lambda). Then use Rydberg's equation and input the frequency, n=2, and Rydberg's constant into v=R(1/n^2 - 1/n^2) to solve for the n2.
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Re: Sapling HW #11
You know that n1=2 because the wavelength falls under the Balmer series. To find n2, you would use a modified form of the Rydberg equation for frequency. First, you find frequency using the equation
. From there the modified form of the Rydberg equation would be (\frac{1}{2^2}-\frac{1}{n^{2}}))
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Re: Sapling HW #11
I had trouble with that same problem, my problem was forgetting to convert from nm to meters. But once you do that you just solve for the frequency and then input that into the equation v = R[1/n1^2 - 1/n2^2] with n1=2 and solve for n2.
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Re: Sapling HW #11
To solve this, make sure you remember to convert nanometers to m in order to do the proper calculations. To find the frequency from the wavelength you would first use c= frequency/wavelength. Once you have the frequency, you plug it into the equation f= (Rydberg's constant) (1/n(final) - 1/n(initial)) with the known n1 value and solve for n2.
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