Achieve HW #6

[KDeguzman_Dis3K]

"When a metal was exposed to photons at a frequency of 1.03×1015 s−1, electrons were emitted with a maximum kinetic energy of 3.90×10−19 J.
Calculate the work function, Φ, of this metal."

What is the equation required to solve this problem? I tried using the equation Ek= hv - workfunction and attempted to figure out the solution by using the provided information, but my answer is incorrect. If someone could help me out with the process, I'd highly appreciate it!

[OishiBhattacharya2K]

First, you plug in the given frequency into the E=hv equation in order to calculate the energy of photons. You then use that energy, and subtract the max kinetic energy (given) from that value in order to get the work function. Hope this helps!

[Gabby Burgess 2I]

Hi,
Yes, you would use the E=hv equation to solve for E(photon). Then you use E(photon)=workfunction+E(Kinetic) and substitute in your known values from the question.
Hope that helps!

[RossLechner3E]

We know the work function will equal the energy of the photon minus the kinetic energy of the emitted electron. We can first solve for the energy of the energy of the photon by using E=hv where v, the frequency, is given. Then we can subtract the kinetic energy from that obtained value and that will yield the work function.

[Sabira Mohammed 3I]

Hi,
You would use the given frequency to find E(photon) using E=hv. Then you would do E(photon)- E(kinetic) to get work function).